soap

SOAP is dead - long live SOAP

First of all do not write SOAP services if you can avoid it! It is over.

If you can not avoid it this package might help.

Service

package main

import (
	"encoding/xml"
	"fmt"
	"net/http"

	"github.com/globusdigital/soap"
)

// FooRequest a simple request
type FooRequest struct {
	XMLName xml.Name `xml:"fooRequest"`
	Foo     string
}

// FooResponse a simple response
type FooResponse struct {
	Bar string
}

// RunServer run a little demo server
func RunServer() {
	soapServer := soap.NewServer()
	soapServer.HandleOperation(
		// SOAPAction
		"operationFoo",
		// tagname of soap body content
		"fooRequest",
		// RequestFactoryFunc - give the server sth. to unmarshal the request into
		func() interface{} {
			return &FooRequest{}
		},
		// OperationHandlerFunc - do something
		func(request interface{}, w http.ResponseWriter, httpRequest *http.Request) (response interface{}, err error) {
			fooRequest := request.(*FooRequest)
			fooResponse := &FooResponse{
				Bar: "Hello " + fooRequest.Foo,
			}
			response = fooResponse
			return
		},
	)
	err := soapServer.ListenAndServe(":8080")
	fmt.Println("exiting with error", err)
}

func main() {
	RunServer()
}

Client

package main

import (
	"encoding/xml"
	"log"

	"github.com/globusdigital/soap"
)

// FooRequest a simple request
type FooRequest struct {
	XMLName xml.Name `xml:"fooRequest"`
	Foo     string
}

// FooResponse a simple response
type FooResponse struct {
	Bar string
}

func main() {
	client := soap.NewClient("http://127.0.0.1:8080/", nil)
	response := &FooResponse{}
	httpResponse, err := client.Call("operationFoo", &FooRequest{Foo: "hello i am foo"}, response)
	if err != nil {
		panic(err)
	}
	log.Println(response.Bar, httpResponse.Status)
}

Apache License Version 2.0